JimWelsh
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Total Posts
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1426
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- Joined: 1/22/2010
- Location: Angwin, CA, US
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Re:Culture Journal, Species: [Dunaliella tertiolecta]
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Tuesday, March 11, 2014 1:17 AM
Since you asked...... Zach, your math is overall good, except that you are using too many significant figures in your calculations that you almost certainly cannot support with facts. For example: Your "about 12 cups", when converted to mL, well, yeah, sure, if I Google "convert 12 cups to ml", then I, too, get an answer of 2839.06. However, in order to use such a precise number, then you would HAVE to be able to measure your cups to within 0.01 ml = 0.0000423 cups accuracy. Are you really asserting that (A) the measurement markings on the side of the jar are that accurate, and (B) that you can visually discern the meniscus with that accuracy, and (C) that the meniscus was exactly on the mark on the side of the jar to that degree of accuracy (never mind the effects of temperature and barometric pressure on the volume of the liquid)? I very seriously doubt all three, and you would need all three to support using a number like 2839.06 in your calculations. Since you used "about 12 cups" in reference to a VERY coarse measurement marking, then you can probably honestly claim just 2 significant figures, *maybe* 3, in the volume measurement, regardless which units you are using. So, re-doing the math, I get: 2840 * 2,910,000 = 8,260,000,000 or even 8,300,000,000 (notice that even though the answer on the calculator when you multiply 2840 * 2,910,000 is 8,264,400,000, you still don't get any "free" significant figures out of the deal. Your numbers are only as accurate as the accuracy of the least accurate number(s) you are starting with). Let me give you another example. As I write this, I am sipping a glass of wine. That glass has a diameter at the mouth of 6.3 cm, which is the most accurate measurement I can make with the tool available to me (a metric ruler with mm divisions). If I wish to calculate the circumference of said glass, would you agree that I can say with any real integrity that the circumference is 19.7920337176 cm (the answer I get when I Google "what is 6.3 times pi")? I hope that you would agree that, considering the relatively coarse units of my original diameter measurement (6.3 cm), at best, I can only claim to know the circumference to within two significant figures as well. Accordingly, I can only honestly estimate the circumference to be 20 cm, even though I might be able to estimate pi to many, many decimal places. The extra significant figures in the value of pi I use do not make up for the relatively inaccurate measurement of the diameter my calculation is based upon. Other than that, your math looks great!
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